Question

Find the valueof y for which the distance between the points P(2,-3) and Q(10,y) is 10 units.​

Answer 1

Answer:

Step-by-step explanation:√(x2-x1)^2+(y2-y1)^2,√10-2^2+y+3^2=√8^2+y^2+9+6y=√73+y^2+6y=10,73+y^2+6y=100,y^2+6y=100-73=27,y^2+6y-27=0 y^2+9y-3y-27=0,y(y+9)-3(y+9)=y-3 ,y+9=y=3 or-9