Question

find the valueQ,ij root3 sinQ=cosQ

Answer 1

Answer:

Step-by-step explanation:

SinA + cosA = √3

Squaring on both sides we get,

(SinA + cosA)² = (√3)²

Sin²A + cos²A +2sinAcosA = 3

1 + 2sinAcosA = 3

2sinAcosA = 3-1

SinAcosA = 2/2

sinAcosA = 1......................(!)

tanA+cotA = 1

sinA/cosA + cosA/sinA = 1

sin²A + cos²A /sinAcosA = 1

1/sinAcosA = 1

sinAcosA = 1.....................(!!)

! = !!

thus tanA + cotA = 1