Question

find the values ....​

Answer 1

Answer:

I'm solving this As per Pythagoras theorem ,

In ∆PQR ,

H^2 = B^2 + P^2

H^2 = 2^2 +5^2

H^2 = 4+25

PR =√29

IN ∆PQS ,

QS = QR+RS (QR=RS=2 , given )

= 2+2 =>4

H^2 = B^2 + P^2

PS^2 = 4^2 + 5^2

PS^2 = 16 +25

PS = √41