Question

find the values af p so that the equation
(P-4) x² -2 (P-4) x + 4 =0
has real roots.​

Answer 1

Answer:

a=(p-4)

b= -2(p-4)

c= 4

since the roots are equal,

we will use.  b^2 -4ac =0

put the respective values of a which i've written above in the above mentioned formula and get the answer

Step-by-step explanation:

Answer 2

Answer:

f is N(0, 1) then p(t) = f°, which yields 6 = Vave(x2 ) (the root mean square, ... It is easy to verify that ( 2.51) and (2.52) satisfy the conditions for a p- ...