Question

Find the values for a and b that would make the equality true.
7(ay^2+by-3) = 14y^2-7y-21

Answer 1

Answer:

a=2 & b= -1

Step-by-step explanation:

7(ay^2+by-3) = 14y^2-7y-21

LHS can be written as 7ay^2 + 7by - 21

and RHS is 14y^2-7y-21.

So, let us consider the coefficient of y^2 in both the equations .

7a = 14 ----> a=2

If we consider the coefficients of y, we get

7a = -7

a= -1