Question

find the values for k in the eq k^2 -3k-2=0​

Answer 1

Answer:

$k {}^{2} - 3k - 2 \\ k {}^{2} - 2k - k - 2 \\ k(k - 2)1(k - 2) \\ (k + 1)(k - 2) \\ k = 2 \\ k = - 1$

I think it will help you thanks

Answer 2

Answer:

k=[(3+√17)/2,3-√17)

Step-by-step explanation:

k²-3k-2=0

(k-3/2)²-(3/2)²-2=0

k=(±√(17)+3)/2