Math, asked by shireenmujawar7943, 5 months ago

find the values for the letters used in the following operations 6888 +12B4=81AA

Answers

Answered by samhi71

1

Answer:

A=2 B=3

Step-by-step explanation:

6888+1234=8122

Answered by malapatilakshmireddy

0

Answer:

if B. = 1 , AA= 8102

if B = 2, AA = 8112

IF B = 3, AA = 8122.....

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