find the values no2 ans with methods
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Answered by
2
Answer:
Step-by-step explanation:
Using identity
(a+b)²=a²+b²+2ab
(6)²=a²+b²+2×8
36=a²+b²+16
20=a²+b²
Now,
a³+b³=(a+b)(a²+b²-ab)
a³+b³=(6)(20-8)
a³+b³=6×12
a³+b³=72
gargnakul67:
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Answered by
0
Answer:
342
Step-by-step explanation:
a+b =6
a=6-b...(1)
ab=8
(6-b)-b=8 (from1)
6-2b=8
-2b=8-6
-2b=2
b=2/-2
b=-1
a=6-b
a=6-(-1)
a=6+1
a=7
a^3+b^3
=7^3+(-1)^3
=343-1
=342
(6-b)-b=8 (from1
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