Math, asked by venkat129, 7 months ago

Find the values of 2

60° − 22

45° − 2

30° + 22

30° +

3

4

2

45°. I need this ASAP pls​

Answers

Answered by kumarabhay1651
1

Answer:

we have to evaluate

2\tan^2 45^{\circ}+\cos^2 30^{\circ}-\sin^2 60^{\circ}2tan

2

45

+cos

2

30

−sin

2

60

\tan 45^{\circ}=1tan45

=1

\cos 30^{\circ}=\frac{\sqrt3}{2}cos30

=

2

3

\sin 60^{\circ}=\frac{\sqrt3}{2}sin60

=

2

3

2\tan^2 45^{\circ}+\cos^2 30^{\circ}-\sin^2 60^{\circ}2tan

2

45

+cos

2

30

−sin

2

60

2(1)^2+(\frac{\sqrt3}{2})^2-(\frac{\sqrt3}{2})^22(1)

2

+(

2

3

)

2

−(

2

3

)

2

2+\frac{3}{4}-\frac{3}{4}2+

4

3

4

3

22

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