Math, asked by debashreebanerjee78, 4 months ago

Find the values of 2 root 2 Cos45°.cos60° + 2 root 3 Sin60°. tan60° -cos0º​

Answers

Answered by vishvasak
2

Step-by-step explanation:

2 \sqrt{2} \times  \cos(45)  \times  \cos(60)  + 2 \sqrt{3}  \sin(60)  \times  \tan(60) -  \cos(0)

 = 2 \sqrt{2} \times( 1 \div  \sqrt{2} ) \times (1 \div 2) + 2 \sqrt{3}( \sqrt{3 }  \div 2) \times  \sqrt{3}  - 1

 = 1 + 3 \sqrt{3}  - 1

 = 3 \sqrt{3}

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