find the values of 3^-1 + 4^-1 ,
( 3^-1 + 4^-1+5^-1)^0,
[ ( 1/3 ^-1 - ( 1/4 ^-1 ] ^-1
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(a) 3^(-1) + 4^(-1) = 1/3 + 1/4 = 7/12
(b) (3^-1 + 4^-1 + 5^-1)^0 = 1 [Any number to the power 0 is equal to 1]
(c) [1/3^(-1) - 1/4^(-1)]^(-1) = [3 - 4]^(-1) = [-1]^(-1) = -1
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Answer:
3^-1 + 4^-1 = 7/12
( 3^-1 + 4^-1 + 5^-1 )^0 = 1
[ { (1/3)^-1 } - { ( 1/4 )^-1} ]^-1 = -1
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