Find the values of 3sin 2 20 o - 2tan 2 45 o + 3sin 2 70 o
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3sin²20°-2tan²45°+3sin²70°
=3sin²20°-2×(tan45°)²+3{sin(90°×1)-20°}²
=3sin²20°-2×(1)²+3cos²20°
=3(sin²20°+cos²20°)-2
=3-2 [∵, sin²20°+cos²20°=1]
=1 Ans.
=3sin²20°-2×(tan45°)²+3{sin(90°×1)-20°}²
=3sin²20°-2×(1)²+3cos²20°
=3(sin²20°+cos²20°)-2
=3-2 [∵, sin²20°+cos²20°=1]
=1 Ans.
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