Question

find the values of 'a' and 'b':
3-√5÷3+2√5 = a√5-19/11 b​

Answer 1

Step-by-step explanation:

Step-by-step explanation:

=(3-√5)/(3+2√5)

=(3-√5)/(3+2√5)×(3-2√5)/(3-2√5)

=(3-√5)(3-2√5)/(3+2√5)(3-2√5)

=[3(3-2√5)-√5(3-2√5)]/(3²-(2√5)²

=(3²-6√5-3√5+2(5))/(9-4(5))

=(9-9√5+10)/(9-20)

=(19-9√5)/(-11)

=–(19-9√5)/ 11

= –(19-9√5)/11

=(-19+9√5)/11

=(9√5-19)/11

=9√5/11 - 19/11 = a√5-19/11

Therefore,a=9/11

If it is (a√5-19)/11 then a=9

But according to question,a√5-19/11

So,answer is 9/11