Question

Find the values of a and b for which the equations x + ay + z = 3, x + 2y +2z = b, x + 5y + 3z =9 are consistent.
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Answer 1

Answer:

a= 2, b= 3

Step-by-step explanation:

for the pair of linear equation to be consistent, the values of a1,a2,b1,b2 should be like that

a1/a2≠b1/b2

and here values a and b are like that A1/A2≠b1/b2

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Answer 2

Given :

x + ay + z = 3, x + 2y +2z = b, x + 5y + 3z =9

To Find :

Value of a & b

Solution :

$\frac{a_{1} }{a_{2} }$$\neq$$\frac{b_{1} }{b_{2} }$

For the pair of a linear equation to be consistent, the values of  $a_{1}$, $a_{2}$, $b_{1}$, $b_{2}$should be like that

⇒ $\frac{a_{1} }{a_{2} }$$\neq$$\frac{ b_{1} }{b_{2} }$

and here values a and b are like that

$\frac{a_{1} }{a_{2} }$$\neq$$\frac{b_{1} }{b_{2} }$