Question

Find the values of a and b for which
X=3/4 and x = -2 are the zeroes of the polynomial p(x) = ax² + bx – 6.
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Answer 1

Answer:X=3/4 and x = -2 are the zeroes of the polynomial p(x) = ax² + bx – 6.

X=3/4

A(9/16)+b(3/4)-6=0

A(9/16)+b(3/4)=6

9a/16+12b/16=6

9a+2b=96.....(1)

X=-2

4a-2b-6=0

2a-b-6=0......(2)

Step-by-step explanation:

Answer 2

Answer:

a=4 ,b=5

Step-by-step explanation:

x=3/4. x=-2

4x=3. x+2=0

4x-3=0

( 4x-3)(x+2)=0

4×^2+8x-3x-6=0

4x^2+5x-6=ax^2+bx -6

a=4 b=5