Find the values of a and b, if √2+√3 3√2− 2√3 . = a+b√6.
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Given (
3
2 −2 32 +3 )
=(6 ( 3 −2 )2 +3 )
Rationalize the denominator
=( 6 ( 3 − 2 )2 + 3 )×( 3 + 23 + 2 )
=( 6 ×(3−2)2+3+26 )
=( 65 )+2
=2+( 65 ) 6
by comparing
∴a=2andb=( 6−5 )
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