Question

find the values of a and b if (√3+1)/(√3-1)=a+b√3 *​

Answer 1

Answer:

$a=2, b= 1$

Step-by-step explanation:

$\frac{(\sqrt{3}+1)}{ (\sqrt{3}-1)}=a+b\sqrt{3}$

$\frac{(\sqrt{3}+1)}{ (\sqrt{3}-1)}*\frac{(\sqrt{3}+1)}{ (\sqrt{3}+1)} = a+b\sqrt{3}$

$\frac{(\sqrt{3} +1)^{2} }{3-1} = a+b\sqrt{3}$

$3+1+2\sqrt{3} = 2a + 2b\sqrt{3}$

$2*2+2\sqrt{3} = 2a + 2b\sqrt{3}$

By comparing LHS to RHS

We get,

$a=2, b= 1$