Question

find the values of a and b if 3+√2/3-√2=a+b√2​

Answer 1

Answer:

$\frac{3 + \sqrt{2} }{3 - \sqrt{2} } \\ rationalising \: them \\ \frac{(3 + \sqrt{2} )}{ {3}^{2} - \sqrt{2 {}^{2} } } \\ \frac{9 + 2 + 6 \sqrt{2} }{9 - 2} \\ \frac{11 + 6 \sqrt{2} }{7} \\ so \: a = \frac{11}{7} and \: b = \frac{6}{7}$

HOPE IT HELPS ^_^