Question

find the values of a and b, if 3+√2/3-√2 = a+b√2​

Answer 1

Answer:

The correct answer is this really 5a

Answer 2

Answer:

$\huge\colorbox{yellow}{Given\:-}$

$\frac{3 + \sqrt{2} }{3 - \sqrt{2}} = a + b \sqrt{2}$

$\huge\colorbox{yellow}{To\:Find\:-}$

• The value of a and b

$\huge\colorbox{yellow}{Solution\:-}$

$\frac{3 + \sqrt{2} }{3 - \sqrt{2} }$

$= \frac{3 + \sqrt{2} }{ 3 - \sqrt{2} } \times \frac{3 + \sqrt{2} }{3 + \sqrt{2} }$

$= \frac{9 + 6 \sqrt{2} + 2 }{9 - 2}$

$= \frac{11 + 6 \sqrt{2} }{7}$

$\pink{ = > \frac{11 + 6 \sqrt{2} }{7} = a + b \sqrt{2} }$

Therefore,

• a = 11/7

• b = 6/7

$\huge\colorbox{yellow}{Thank\:You}$

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