Question

Find the values of a and b if
3+√2\3-√2= a +b/2​

Answer 1

Step-by-step explanation:

$3 + \frac{ \sqrt{2} }{3} - \sqrt{2} \\ \frac{9 + \sqrt{2 } - 3 \sqrt{2} }{3} \\ \frac{9 - 2\sqrt{2} }{3} \times 2 \\ \frac{18}{3} - \frac{2 \sqrt{2} }{3}$

therefore a=18/3 and b= -2√2/3