Question

find the values of a and b if 3/(3+2root2) + 2/(3-2root2) = a+b root 2​

Answer 1

Answer:

$3 \div (3 + 2 \sqrt{2} ) + 2 \div (3 - 2 \sqrt{2} ) = a + b \sqrt{2 }$

3(3-2√2)+2(3+2√2) ÷ (3+2√2)(3-2√2) = a+b√2

(9-6√2+6+4√2) ÷ 3^2-2√2^2 = a+b√2