Find the values of ∠A and ∠B if ∠A and ∠B are supplementary such that ∠A=(2x+10)° and ∠B=(6x−46)°.
urgent help needed
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Answer:
supplementary angles means their sum will be equal to 180 so
<A+<B= 180°
putting value of <A and <B
(2x+10°)+(6x-46°)=180°
8x-36°=180°
8x=216°
x= 216°/8
x = 27
<A= 2*27+10 = 64°
<B = 6*27-47=116°
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