find the values of a and b if both (x-2) and (2x-1) are the factors of ax²+5x+b
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Answer:
case:1
x-2 is factor x=2
4a+10+b=0
case:2
2x-1 is factor x=1/2
a/4+5/2+b=0
a+10+4b=0
solving case1 & case2
4a+b+10=0
4a+16b+40=0
15b+30=0
15b=-30
b=-2
put b=-2in case1
4a-2+10=0
4a=-8
a=-2
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