Find the values of 'a' and 'b' if root3-1/root3+1=a+b*root3 please answer
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Step-by-step explanation:
√3-1/√3+1= a+b*√3
√3-1/√3+1×√3-1/√3-1 = a+√3b ( conjugate )
(√3+1)²/(√3)²-(1)² = a + √3b
( using idy. a²-b² = (a+b)(a-b)
3+2√3+1/3-1 = a+√3b
4+2√3 = 2(a+√3b)
2(2+√3) = 2(a+√3b)
so, by comparing ..
a = 2 , b = 1
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a=2 and b=-1 as a+b root 3
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