Question

find the values of a and b if the zeroes of the polynomial X^2+(a+1)x+b are 2 and -3.

Answer 1

value of a is zero and b is -6

Answer 2

Hello!!

This is your answer.

Given :
x² + (a + 1)x + b
and two Zeroes are 2 and -3.

Comparing the polynomial with ax²+ bc + c, we get
a = 1, b = a + 1 and c = b.

Now,
Sum of zeroes = $\frac{-b}{a}$
=> 2 + (-3) = $\frac{-(a+1)}{1}$
=> -1 = -a - 1
=> a = 0.

$AND$


Product Of Zeroes = $\frac{c}{a}$
=> 2 × -3 = $\frac{b}{1}$
=> -6 = b
=> b = -6.

Hence, a = 0 and b = -6.

Hope You Got It