Question

find the values of a and b if they are the zeroes of the polynomial x^2+ax+b

Answer 1

Given,
first zero = a
second zero = b
Sum of the zeroes,
a + b = -a / 1
a + b = -a
a + a + b = 0
2a + b = 0 .....(1)
Product of zeroes,
ab = b/1
ab = b
a = b/b
a = 1
Substituting the value of a in (1),
2(1) + b = 0
2 + b = 0
b = -2
Hence,
a = 1
b = -2
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