Find the values of a and b if they are the zeroes of the polynomial x^2+ax+b?
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sum of roots of a polynomial
= x+y= -b/a
product of roots
xy = c/a
Here,
a+b= -a/1
a+b= -a
b = -2a
a = -b/2
ab = b/1
-b/2×b= b
☆b = -2
putting 'b' in eqn
a+b =-a
a-2= -a
☆a= 1
= x+y= -b/a
product of roots
xy = c/a
Here,
a+b= -a/1
a+b= -a
b = -2a
a = -b/2
ab = b/1
-b/2×b= b
☆b = -2
putting 'b' in eqn
a+b =-a
a-2= -a
☆a= 1
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