Question

Find the values of a and b if they are the zeros of the polynomial x^2 + ax + b.

Answer 1

$\huge{\underline{\mathfrak{\blue{ANSWER....}}}}$

given=>

p(x) = x^2 + ax + b..

we have zeroes of solution ,,,

a + b = -a$\frac{1}{1}$

a + b = -a

2a +b =0==(1)

similarly,,

a×b =b $\frac{1}{1}$

a × b = b
a = 1...==(2)

substitute in 1....

we get...

2 (1) + b = 0

2 +b = 0

b = -2...

hence, the two zeroes of the solution are,, 1 and -2....

$\huge{\underline{\mathfrak{\red{BE\:BRAINLY}}}}$

Answer 2

Answer:

there are two possible Values of a and b

(1) -1/2 and -1/2

(2) 0 and 0

Step-by-step explanation:

a and b are zeroes of polynomial which means that placing a or b in equation results answer to be zero.

hence, one by one by substituting values of a and b, we get two equations.

a² + a.a +b=0 ⇒ 2a² +b = 0                            .......(1)

b² + ab + b =0                                                 ........(2)

solving both the equations we get two values of a and b.

(1) -1/2 and -1/2

(2) 0 and 0

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