find the values of a and b in
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√3-1/√3+1
=(√3-1/√3+1)(√3-1/√3-1)
=(√3-1)²/((√3)²-(1)²
=3+1-2(√3)(1)/3-1
=4-2√3/2
√3+1/√3-1
=(√3+1/√3-1)(√3+1/√3+1)
=(√3+1)²/((√3)²-(1)²
=3+1+2(√3)(1)/3-1
=4+2√3/2
4-2√3/2 + 4+2√3/2
= (4-2√3+4+2√3)/2
= 8/2
= 4
a=4
b=0
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=(√3-1/√3+1)(√3-1/√3-1)
=(√3-1)²/((√3)²-(1)²
=3+1-2(√3)(1)/3-1
=4-2√3/2
√3+1/√3-1
=(√3+1/√3-1)(√3+1/√3+1)
=(√3+1)²/((√3)²-(1)²
=3+1+2(√3)(1)/3-1
=4+2√3/2
4-2√3/2 + 4+2√3/2
= (4-2√3+4+2√3)/2
= 8/2
= 4
a=4
b=0
Hope it helps you ☺
Please mark as Brainliest ☺
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