Question

Find the values of a and b in each of the following where a and b are rational numbers.

Please answer with explanation. Solve on paper and answer please.​

Answer 1

Answer:

$\frac{( \sqrt{2} + \sqrt{3})(3 \sqrt{2} + 2 \sqrt{3}) }{18 - 12} = a - b \sqrt{6} \\ \frac{6 + 2 \sqrt{6} + 3 \sqrt{6} + 6 }{6} = a - b \sqrt{6} \\ 2 + \sqrt{6} = a + b \sqrt{6} \\ a = 2 \\ b = 1$