Find the values of a and b so that 4x – ( 3a + 5) y = 2 and ( 3b + 1) x – 5y = 4 will have infinite number of solutions.
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Step-by-step explanation:
there should have been 2x − 3y = 12
5x + 3y = 9 -----(I)
2x − 3y = 12 ----- (II)
Add (I) and (II)
7x = 21
x = 3
Putting the value of x = 3 in (I) we get
5(3)+3y=9⇒15+3y=9⇒3y=9−15=−6⇒y=−2
Thus, (x, y) = (3, −6).
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