Find the values of a and b so that polynomial x cube minus x square - 13 x + b has x - 1 and x + 3 x factors
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Answer:
Step-by-step explanation:
polynomial P(x) = x³ - x² -13x + b
There is no a in the equation so i will find value of b only
x-1 is its root so for x =1 P(x) = 0
P(1) = 0
1³ - 1² -(13×1) + b = 0
1 -1 -13 + b = 0
b =13
Similarly x = -3
P(-3) = 0
(-3)³ -(-3)² -13(-3) + b = 0
-27 - 9 +39 + b = 0
b = -3
so value of b is not matching
hence given roots are not correct or equation is missing a somewhere
as question also states that find value of a & b
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