Question

find the values of a and b so that the polynomial (x^3-10x+ax+b) is exactly divisible by (x-1) as well as (x-2).​

Answer 1

f(x)= x³ -10x + ax + b
g(x)= x-1
Let g(x)= 0
x-1=0
x=1
f(1)= 1-10+a+b
0= -9 +a+b
b=9-a
g(x)= x-2
Let g(x)=o
x-2=0
x=2
f(x)= 8-20 + 2a + b
0= -12 +2a +9-a
0= -3 + a
a= 3
b = 9-3
b=6
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Answer 2

Answer:

Step-by-step explanation: