Find the values of a and b so that the polynomial (x4+ax3-7x2-8x+b) is exactly divisible by(x+2) as well as(x+3)
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Answer:
Given : Polynomial x
4
+ax
3
−7x
2
−8x+b is exactly divisible
by (x+2) as well (x+3)
⇒x=−2,−3 are the roots of polynomial
∴(−2)
4
+a(−2)
3
−7(−2)
2
−8(−2)+b=0
16−8a−28+16+b=0
−8a+b=−4 ... (I)
(−3)
4
+a(−3)
3
−7(−3)
2
−8(−3)+b=0
81−27a−63+24+b=0
−27+b=−42 .... (II)
(I) - (II)
Ref. Image
a=2
put a=2 in equation (I)
−16+b=−4
b=−4+16
b=12
∴a=2,b=12
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