Math, asked by khaaki1974597, 1 month ago

find the values of a and b so that the polynomials x^3+10x^2+ax+b is exactly divisible by x-1 as well as x-2​​

Answers

Answered by Anonymous
2

x^3+10x^2+ax+b

if f(x) is divisible by (x−1) and (x−2)

⇒f(1)=0=f(2)

f(1)=1−10+a+b=0

⇒a+b=9

f(2)=8−40+2a+b=0

⇒2a+b=32

∴a=23 b=−14

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