find the values of A and B so that X + 1 and x minus 2 are the factors of x cube +a x square + 2X + b
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Step-by-step explanation: Let f(x)= x³+ax²+2x+b and E₁=equation one
x+1=0 and x-2=0
⇒x= -1 and x= 2
If (x+1) and (x-2) are factors of f(x), then f(-1)=0 and also f(2)=0
⇒ (-1³)+a(-1²)+2(-1)+b=0 and 2³+a(2²)+2(2)+b=0
⇒ -1+a-2+b=0 and 8+4a+4+b=0
⇒ a+b-3=0 and 4a+b+12=0
⇒ a+b= 3·······E₁ and 4a+b= -12········E₂
⇒ (a+b=3)
- (4a+b= -12)
--------------------
-3a+0=15
⇒ -3a=15
⇒ a= -5········E₃
substitute E₃ in E₁
⇒ -5+b=3
⇒ b=3+5
⇒ b=8
∴ a= -5 and b=8
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