Question

Find the values of 'a' and 'b' such that $x^{4} +x^{3} +8x^{2}+ax+b$ is exactly divisible by $x^{2}+1$.

Answer 1

Answer:

a=1

b=7

Step-by-step explanation:

on dividing the polynomial by the given factor we will get the remainder-

                                                  x(a-1)+b-7

now we know that the remainder will be zero coz x^2+1 is a factor of the given p(x) hence a-1=0, a=1

b-7=0, b=7