Question

find the values of a and b when 1/7+3 root 2 =a-b root 2​

Answer 1

Answer:

1/7+3√2 =a-b√2​

a=1/7

b=-3

Answer 2

Answer:

a = 7 and b = - 3

Step-by-step explanation:

$\frac{1}{7 + 3 \sqrt{ 2} } = a - b \sqrt{2} \\ 7 + 3 \sqrt{2} = \frac{a - b \sqrt{2}}{1} \\7 + 3 \sqrt{2} = a - b \sqrt{2} \\ \\So, \\The \:value \:of \:a = 7 \:and\: b = - 3$