Question

find the values of A and P if the equation xcosA+ysinA=p is the normal form of the line√3+y+2=0

Answer 1

Answer:

Given equation is x√3 + y + 2 = 0

x√3 + y = - 2

- x√3 - y = 2

Dividing the equation with 2

- x√3/2 - y/2 = 1

x cos 210° + y sin 210° = 1

This is in the form of x cos A + y sin A = P

A = 210° and P = 1

Answer 2

Answer:

A8l=2020000000000000