Question

Find the values of A,B ax2+bxy+3y2-5x-2y-3=0

Answer 1

Answer:

a=3 and b= 0.

GIVEN: ax^2 + bxy + 3y^2 - 5x - 2y -

3 = 0

To find the value if a and b.

SOLUTION:

Equation of circle =>

( ax^2 + 2hxy+by^2 + 2gx + 2fy+c = 0)

is a circle only if a= b and h=0

ang given equation of circle=>

( ax^2 +bxy + 3y^2 - 5x -2y -3= 0)

By comparing,we get

2h= b, from above h= 0

Therefore b= 0.

And a= b. ( b belong to equation of circle)

So, a= b= 3.

Therefore a= 3.

Thats why a=3 and b= 0.