Question

Find the values of a for which the roots of the equation (2a – 5)x2

– 2 (a – 1) x + 3 = 0 are equal.
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Answer 1

Answer:

in cylinder

diameter is 12 cm

hence radius will be 6cm

height is 15 cm

volume of cylinder is

πr^2h

π ×6×6×15 cm ^3

now, volume of 1 toy

2/3 × πr^3 + 1/3 πr^2 h

1/3 πr^2 ( 2r + h)

height of cone is 3 times r

h = 3r

as 12 toys were recasted..

volume of 12 toys = volume of cylinder

12 ×1/3 πr^2 ( 2r + h) = πr^2h

4 πr^2 ( 2r + 3r ) = π ×6×6×15

4 r^2 (5r) = 6×6×15

r^3 = 6 ×6×15/4×5

r ^3 = 3 ×3×3

r = 3 cm

radius of sphere is 3 cm

height of conical part is 3 ×3 = 9 cm

height of toy is 3 +9 = 12cm

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Find the values of a for which the roots of the equation (2a – 5)x2

Find the values of a for which the roots of the equation (2a – 5)x2– 2 (a – 1) x + 3 = 0 are equal.

Find the values of a for which the roots of the equation (2a – 5)x2– 2 (a – 1) x + 3 = 0 are equal.