find the values of a>0 for which both the roots of equation ax^2-(a+1)+a-2=0 are greater than 3
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Answered by
0
Answer:
Given (1−a
2
)x
2
+2ax−1=0
Usind sri dharacharya formula
x=
2(1−a
2
)
−2a±
4a
2
+4(1−a
2
)
x=
(1+a)(1−a)
−a±1
x=
a−1
1
or x=
a+1
1
If a>1 the roots will both be positive, but we require a>2 for both roots to be less than 1.
Therefore a>2
Answered by
0
Answer:
please make brainlist
Given (1−a
2
)x
2
+2ax−1=0
Usind sri dharacharya formula
x=
2(1−a
2
)
−2a±
4a
2
+4(1−a
2
)
x=
(1+a)(1−a)
−a±1
x=
a−1
1
or x=
a+1
1
If a>1 the roots will both be positive, but we require a>2 for both roots to be less than 1.
Therefore a>2
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