Question

Find the values of a such that PQ = QR, where P, Q and R are the points whose coordinates are (6, - 1), (1, 3) and (a, 8) respectively.

Answer 1

Answer:

Coordinate of point P,Q and R are P(6,-1),Q(1,3) and R(x,8)

Given, PQ=QR

So by distance formula we have,

Distance between two points =

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

PQ=

(6−1)

2

+(−1−3)

2

=

25+14

=

41

∴PQ

2

=41=QR

2

but, QR

2

=(x−1)

2

+25

41=x

2

+1−2x+25

⇒41=x

2

+1−2x+25

⇒x

2

−2x+26=41

⇒x

2

−2x−15=0

⇒x

2

−5x+3x−15=0

⇒x(x−5)+3(x−5)=0

⇒(x+3)(x−5)=0

⇒x=−3,5

please brainliest mark

Answer 2

Step-by-step explanation:

there you go hope you understand mate