find the values of ABC such that the number is a,10 b, c, 31 are in AP
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As the numbers are in AP therefore,
10-a = b-10
b+a=20..................(1)
Also
b-10=c-b
2b=10+c..................(2)
And
31-c=10-a....................(3)
Solving eqns 1,2,3 we get
a=3
b=17
C=24
Cheers
10-a = b-10
b+a=20..................(1)
Also
b-10=c-b
2b=10+c..................(2)
And
31-c=10-a....................(3)
Solving eqns 1,2,3 we get
a=3
b=17
C=24
Cheers
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