Find the values of all trigonometric functions of (1) 120° (it) 150°.
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Sin(180-x)=sinx
Cos(180-x)= -cosx
Sin 120=
sin120=√3/2
Cos120=-1/2
Tan120=-√3
Cot120= -1/√ 3
Sec120=-2
Cosec120=2/√3
Cos(180-x)= -cosx
Sin 120=
sin120=√3/2
Cos120=-1/2
Tan120=-√3
Cot120= -1/√ 3
Sec120=-2
Cosec120=2/√3
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