Question

find the values of alpha and beta 2x^-7x-22=0​

Answer 1

Answer:

X=2

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Answer 2

QUESTION :

find the values of alpha and beta 2x^-7x-22=0

ANSWER :

$\alpha \: and \: \beta \: are \: the \: \\ zeroes \: of \: the \: polynomial.$

TO FIND THE

$\alpha \: and \: \beta$

WE have to factorised it:

$2 {x}^{2} - 7x - 22 = 0$

This equation is in the form of

$a {x}^{2} + bx + c = 0$

1. WE have to split the middle term in such a way that it's sum equal to b i.e. -7 and product will be a×c.

$2 {x}^{2} - 11x + 4x - 22$

TAKING common factor

$2x(x - 11) + 4(x - 11)$

$(2x + 4)(x - 11) \: are \: the \: zeroes$

FINAL ANSWER :

$2x + 4 = 0 \\ 2x = - 4 \\ x = - 2$

$x - 11 =0 \\ x = 11$

so,

$\alpha \: and \: \beta \\ are - 2 \: and \: 11$