Math, asked by parikumari9933, 5 months ago

Find the values of and y in the following parallelogram

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Answers

Answered by vtanvins5427
2

Step-by-step explanation:

So we know that parallelograms diagonals bisect (divide into 2 equal halves) each other.

So for that reason x+8=16-x

Solving, x=16-x-8 (Transposition)

x+x=8

2x=8

x=4

And then 2y+13=5y+4

Solving, 2y-5y=4-13

-3y=9

y= -3

So finally x=4 and y= -3

Mark it as the brainliest answer....

Answered by Flaunt
142

\sf\huge\bold{Solution}

Given

ABCD is parallelogram in which AC and BD are two Diagonals.

To Find

Value of x and y

Recall some properties of Parallelogram:

  • Opposite sides are parallel.
  • Diagonals bisect each other into two equal congruent triangle.
  • Interior angle sum is equal to 360°
  • Parallelogram having four sides and four vertex.

Here ,we use second property of parallelogram

Bisection of Diagonals.

AO=OC and BO=OD

\sf \longmapsto \: x + 8 = 16 - x

\sf \longmapsto \: x + x = 16 - 8

\sf \longmapsto2x = 8

 \sf \: x = 4

Now,BO=OD

\sf \longmapsto5y + 4 = 2y + 13

\sf \longmapsto5y - 2y = 13 - 4

\sf \longmapsto3y = 9

 \sf \: y = 3

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