Find the values of 'b' and 'c', if the division of x²+bx+c by (x- 1) leaves remainder zero and by (x+2) leaves remainder 12
Answers
Answer:
Therefore, the required ratio = 325 cents : 925 cents
= 325cents925cents
= 325925
= 25×1325×37
= 1337
= 13 : 37.
4. Simplify the following ratios:
(i) 223 : 414
(ii) 3.5 : 215
(iii) 112 : 23 : 116
Solution:
(i) 223 : 414
= 113 : 174
Now multiply each term by the L.C.M. of the denominators
= 113 × 12 : 174 × 12, [Since, L.C.M. of 3 and 4 = 12]
= 44 : 51
(ii) 3.5 : 215
= 3510 : 115
Now multiply each term by the L.C.M. of the denominators
= 3510 × 10 : 115 × 10, [Since, L.C.M. of 10 and 5 = 10]
= 35 : 22
(iii) 112 : 23 : 116
= 32 : 23 : 76
Now multiply each term by the L.C.M. of the denominators
= 32 × 6 : 23 × 6 : 76 × 6, [Since, L.C.M. of 2, 3 and 6 = 6]
= 9 : 4 : 7
Step-by-step explanation:
Answer:
Therefore, the required ratio = 325 cents : 925 cents
= 325cents925cents
= 325925
= 25×1325×37
= 1337
= 13 : 37.
4. Simplify the following ratios:
(i) 223 : 414
(ii) 3.5 : 215
(iii) 112 : 23 : 116
Solution:
(i) 223 : 414
= 113 : 174
Now multiply each term by the L.C.M. of the denominators
= 113 × 12 : 174 × 12, [Since, L.C.M. of 3 and 4 = 12]
= 44 : 51
(ii) 3.5 : 215
= 3510 : 115
Now multiply each term by the L.C.M. of the denominators
= 3510 × 10 : 115 × 10, [Since, L.C.M. of 10 and 5 = 10]
= 35 : 22
(iii) 112 : 23 : 116
= 32 : 23 : 76
Now multiply each term by the L.C.M. of the denominators
= 32 × 6 : 23 × 6 : 76 × 6, [Since, L.C.M. of 2, 3 and 6 = 6]
= 9 : 4 : 7