Question

Find the values of currents Ii, 12 and 13 using nodal analysis.
2 20
V
V
1002
WW
250
203
sa
340
50 V
25 V​

Answer 1

Answer:

As no current flows in arm BE so the potential difference across R

1

will be zero.

Now applying Kirchhoff's law for loop AFEBA, 6+1+3=2i+3i or i=2A

The potential difference across A and D along AFD , V

A

−2i+1−3i=V

D

or V

A

−V

D

=5i−1=5(2)−1=9V