Question

Find the values of dx and dy to solve the simultaneous equation 3x-4y=10; 4x+3y=5

Answer 1

1. 3x-4y=10;4x+3y=5
2. dx = 10/5. -4/3 and crossmultiple both=10×3-5×(-4) = 30-(-20) =50
3. dy = 3/4 10/5 = 3×5-4×10 = 15-40 = -25
4. hence DX=50 and dy=-25

Answer 2

Answer:

Dx = 50

Dy = -25

Explanation:-

Dx = 10×3 - 5×(-4)

=30-(-20)

=50

Dy = 3×5 - 4×10

=15-40

-25